Respuesta :

[tex]\bf \cfrac{4k+2}{k^2-4}\cdot \cfrac{k-2}{2k+1}\implies \cfrac{2(2k+1)}{k^2-2^2}\cdot \cfrac{k-2}{2k+1}\implies \cfrac{2\underline{(2k+1)}}{\underline{(k-2)}(k+2)}\cdot \cfrac{\underline{k-2}}{\underline{2k+1}} \\\\\\ \cfrac{2}{k+2}\cdot \cfrac{1}{1}\implies \cfrac{2}{k+2}[/tex]
Sonictanker777

Answer:

D: 2/k + 2

Step-by-step explanation:

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