Answer:
For any value of P & Q except when both are equal , we get One solution of equation.
Step-by-step explanation:
Given: Linear Equation, Qx - 6 = Px - 103
This equation has exactly 1 solution.
To find: Value of P and Q
First we solve the linear equation for value of x,
Qx - 6 = Px - 103
Transpose Px to LHS ( Left hand side ) we get,
Qx - Px - 6 = -103
Transpose 6 to RHS ( Right hand side ) we get,
Qx - Px = -103 + 6
Qx - Px = -97
taking x common in LHS, we get
( Q - P ) x = -97
Traspose ( Q - P ) to RHS, we get
[tex]x=\frac{-97}{Q-P}[/tex]
[tex]x=\frac{-97}{-(P-Q)}[/tex]
[tex]x=\frac{97}{P-Q}[/tex]
Thus, we are get only 1 value of x but it exist if P ≠ Q
otherwise no solution exist for the given linear Equation.
Therefore, For any value of P & Q except when both are equal , we get One solution of equation.
