For the purpose of the problem we can consider only the motion on the x-axis (horizontal direction).
We have two forces:the horizontal component of the force F of 3320 N acting forward, and the backward force of 550 N.
The horizontal component of the forward force is
[tex]3320 N \cdot cos 30^{\circ} = 2875 N[/tex]
So, the net force is
[tex]F_{net} = 2875 N - 550 N =2325 N[/tex]
in the forward direction.
