Respuesta :
the answer is the option A
let
y--------------- > short side
applying the Pythagorean theorem
(x+4)²=y²+(x+3)²
y²=(x+4)²-(x+3)²-------> x²+8x+16-x²-6x-9=2x+7
y=√(2x+7)
let
y--------------- > short side
applying the Pythagorean theorem
(x+4)²=y²+(x+3)²
y²=(x+4)²-(x+3)²-------> x²+8x+16-x²-6x-9=2x+7
y=√(2x+7)
Let us try and solve it analytically. We have that the side=x+3 together with the short side=s and the diagonal=x+4 satisfy the Pythagorean Theorem. Then we have that [tex](x+4)^2=(x+3)^2+s^2[/tex]. This yields [tex]s^2+x^2+6x+9=x^2+8x+16[/tex]
which yields s^2=2x+7, hence a) is the correct answer.
which yields s^2=2x+7, hence a) is the correct answer.