Respuesta :
The equation of the reaction is:
Na2CO3 + AgNO3 → NaNO3 + Ag2CO3
but this equation, not a balanced equation so let's make it a balanced equation:
- we will start with Na number of atoms, we should make the Na atom number is equal on both sides.So we put 2 NaNO3 instead of NaNO3
- and then the Ag atom, we put 2AgNO3 instead of AgNO3 to make the number of Ag on each side are equals.
So the final balanced equation for this reaction is:
Na2CO3(aq) + 2AgNO3(aq) → 2NaNO3(aq) + Ag2CO3(s)
SO know we have number of Na on each side = 2
number of Ag on each side = 2
Na2CO3 + AgNO3 → NaNO3 + Ag2CO3
but this equation, not a balanced equation so let's make it a balanced equation:
- we will start with Na number of atoms, we should make the Na atom number is equal on both sides.So we put 2 NaNO3 instead of NaNO3
- and then the Ag atom, we put 2AgNO3 instead of AgNO3 to make the number of Ag on each side are equals.
So the final balanced equation for this reaction is:
Na2CO3(aq) + 2AgNO3(aq) → 2NaNO3(aq) + Ag2CO3(s)
SO know we have number of Na on each side = 2
number of Ag on each side = 2
The balanced chemical reaction between [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{AgN}}{{\text{O}}_3}[/tex] is
[tex]\boxed{{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( s\right)}[/tex]
Further Explanation:
The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as a balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.
The steps to balance a chemical reaction are as follows:
Step 1: Complete the reaction and write the unbalanced symbol equation.
In this reaction, [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] reacts with [tex]{\text{AgN}}{{\text{O}}_3}[/tex] to form [tex]{\text{NaN}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex]. The unbalanced chemical equation is as follows:
[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + {\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to {\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]
Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.
• On reactant side,
Number of sodium atoms is 2.
Number of carbon atoms is 1.
Number of oxygen atom is 6.
Number of silver atom is 1.
Number of nitrogen atom is 1.
• On product side,
Number of sodium atom is 1.
Number of carbon atoms is 1.
Number of oxygen atom is 6.
Number of silver atoms is 2.
Number of nitrogen atom is 1.
Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. But nitrogen atoms on both sides of the equation are already equal. To balance the number of sodium and silver atoms, multiply [tex]{\text{AgN}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{NaN}}{{\text{O}}_{\text{3}}}[/tex] by 2. So the equation is,
[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + \boxed2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to \boxed2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]
Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. But these are already balanced. Now the reaction is,
[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]
Step 5: So the balanced chemical equation is given as follows:
[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]
Learn more:
1. Balanced chemical equation: https://brainly.com/question/1405182
2. Identification of all of the phases of the reaction: https://brainly.com/question/8926688
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Chemical reaction and equation
Keywords: balanced chemical reaction, reactant side, product side, AgNO3, NaNO3, Ag2CO3, Na2CO3, nitrogen atom, sodium atoms, oxygen atoms, carbon atoms, silver atoms.
