Respuesta :
The $ -(Br) at that instant is calculated as follows
BrO3 + 5Br ---> 3Br2 + 3 H2o
by use of reacting ratio BrO3 to Br2 which is 1:3
therefore $ of Br = 3 x (1.5 x10^-2)= 4.5 x10^-2
BrO3 + 5Br ---> 3Br2 + 3 H2o
by use of reacting ratio BrO3 to Br2 which is 1:3
therefore $ of Br = 3 x (1.5 x10^-2)= 4.5 x10^-2
Answer:
7.5 M/s
Explanation:
The equation of Reaction is given as;
BrO^3- + 5Br^- + 6H^+ --------------> 3Br2 + 3H2O. ----------------------------(1)
Rate of Reaction is the speed in which reaction take place for the transformation of reactants to products.
For the reaction (1) above;
===> - (∆[BrO^3-]/ ∆t) = -(∆Br^-])/∆t = -∆[H^+] /∆t = ∆[Br2]/∆t.
Notice from above that there is negative signs at the Change in the reacti species. This is so, because the Reactants is been used up in the reaction to produce the products
NB : I did not raise the number of the moles to the power of each species to avoid clumsiness.
We are given that; - (∆[BrO^3-]/ ∆t) = 1.5 × 10^-2 m/s; -(∆Br^-])/∆t = x m/s.
1 mole of BrO3^- = 5 mole of Br^-
So, 5 × 1.5 ×10^-2 .
= 7.5 × 10 ^-2 M/s