abcd is an isosceles trapezoid with legs AB and CD and base BC. If the length of AB is 7y-4, the length of BC s 4y-6 and the length of CD is 8y-18, find the value of y. 30 points for brainliest!

We are told that the legs of the isosceles trapezoid are AB and CD

AB = 7y - 4
CD = 8y - 18

In any isosceles trapezoid, the two legs are of equal length.
Therefore, AB = CD

⇒ 7y - 4 = 8y - 18

Add 18 to both sides of the equation
7y - 4 + 18 = 8y - 18 + 18
7y + 14 = 8y

Subtract 7y from both sides of the equation
7y - 7y + 14 = 8y - 7y
14 = y
⇒ y = 14

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ahirohit963 ahirohit963 · Answer 2 · 2021-11-25T09:36:04+01:00

The value of 'y' in the isosceles trapezoid ABCD is 14 and this can be determined by using the properties of isosceles trapezoid.

Given :

ABCD is an isosceles trapezoid with legs AB and CD and base BC.
If the length of AB is (7y - 4), the length of BC s (4y - 6) and the length of CD is (8y - 18).

The two legs are of equal length In any isosceles trapezoid that means:

7y - 4 = 8y - 18

Add 18 on both sides in the above equation.

7y - 4 + 18 = 8y - 18 + 18

7y + 14 = 8y

Now, subtract 7y on both sides in the above equation.

7y + 14 - 7y = 8y - 7y

Simplify the above expression in order to get the value of 'y'.

y = 14

For more information, refer to the link given below:

https://brainly.com/question/19273676