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A 6.0 l container holds a sample of hydrogen gas at 150 kpa. if the pressure increases to 2 atm and the temperature remains constant, what will the volume be?

Respuesta :

I’m doing it right but I believe it’s 0.22

Answer:

The volume will be 4.44 L

Explanation:

Data:

First volume, V1 = 6 L

First pressure, P1 = 150 kPa -> 150 kPa * 1 atm/101.325 kPa = 1.48 atm

Second pressure, P2 = 2 atm

Second volume, V2 = ? L

From Boyle's law:

P1*V1 =P2*V2

V2 = P1*V1/P2

V2 = 1.48*6/2

V2 = 4.44 L

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