The following is missing from the task above:
LiClO4(s) →LiCl(s) + 2O2(g)
m(LiClO4)=100g
a) m(O2)=?
From the reaction we got the following number of moles ratio:
n(LiClO4) : n(02) = 1 : 2
So, from the ratio, we can determine number of moles from O2:
n(02)= n(LiClO4) x 2 = (m/M) x 2 = 100/106.4 x 2= 1.9 mole
Now we can calculate the mass of oxygen:
m(O2)=n x M = 1.9 x 32 = 60.15 g
b) V(O2)=?
Now when we have the value of the mass of oxygen, we can calculate its volume with density equation:
d(O2)=m(O2)/V(O2) ⇒ V(O2)= m(O2)/d(O2)
V(O2) = 60.15 / 1.43
V(02) = 42.06 L
