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The volume of a gas is 4.00 liters at 293 k and constant pressure. for the volume of the gas to become 3.00 liters, the kelvin temperature must be equal to

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Dejanras
Answer is: new temperature is 219,75 K.
V₁(gas) = 4,00 L.
T₁(gas) = 293 K.
T₂(gas) = ?.
V₂(gas) = 3,00 L.
Charles' Law:  The Temperature-Volume Law - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:
V₁/T₁ = V₂/T₂.
4,00 L/ 293 K = 3,00 L /  T₂.
T₂ = 219,75 K.

Answer:

3.00 * 293 / 4.00

Explanation: