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Answer: The gas formed by the reaction of sodium sulfite and hydrochloric acid is [tex]SO_2[/tex]
Explanation:
When sodium sulfite reacts with hydrochloric acid, it leads to the formation of many products.
The chemical equation for the reaction of two reacts are:
[tex]Na_2SO_3(s)+2HCl(aq.)\rightarrow 2NaCl(aq.)+SO_2(g)+H_2O(l)[/tex]
By Stoichiometry of the reaction:
1 mole of solid sodium sulfite reacts with 2 moles of aqueous hydrochloric acid to produce 2 moles of aqueous sodium chloride, 1 mole of sulfur dioxide gas and 1 mole of water molecule.
Hence, the gas formed by the reaction of sodium sulfite and hydrochloric acid is [tex]SO_2[/tex]
The gas formed by the reaction of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_3}[/tex] with HCl is [tex]\boxed{{\text{S}}{{\text{O}}_2}}[/tex]
Further Explanation:
The five types of chemical reactions are as follows:
1. Combination reactions:
These reactions are also known as a synthesis reaction. These are the reaction in which two or more reactants combine to form single product. These are generally accompanied by the release of heat so they are exothermic reactions.
Examples of combination reactions are as follows:
(a) [tex]{\text{Ba}}+{{\text{F}}_2}\to{\text{Ba}}{{\text{F}}_2}[/tex]
(b) [tex]{\text{CaO}}+{{\text{H}}_2}{\text{O}}\to{\text{Ca}}{\left({{\text{OH}}}\right)_2}[/tex]
2. Decomposition reactions:
The opposite of combination reactions is called a decomposition reaction. Here, a single reactant gets broken into two or more products. Such reactions are usually endothermic because energy is required to break the existing bonds between the reactant molecules.
Examples of decomposition reactions are as follows:
(a) [tex]2{{\text{H}}_2}{{\text{O}}_2}\to2{{\text{H}}_2}{\text{O}}+{{\text{O}}_2}[/tex]
(b) [tex]2{\text{NaCl}} \to{\text{2Na+C}}{{\text{l}}_2}[/tex]
3. Displacement reactions
Also known as replacement or metathesis reactions. Here, one of the reactants gets replaced by the other one. Generally, the more reactive element displaces the less reactive element. Both metals and non-metals can take part in displacement reactions.
Examples of displacement reactions are as follows:
(a) [tex]{\text{Cu}}+{\text{AgN}}{{\text{O}}_3}\to{\text{Ag}}+{\text{Cu}}{\left({{\text{N}}{{\text{O}}_3}}\right)_2}[/tex]
(b) [tex]{\text{C}}{{\text{l}}_2}+{\text{KBr}}\to{\text{B}}{{\text{r}}_2}+{\text{KCl}}[/tex]
4. Double displacement reactions
These are the reaction in which ions of two compound interchange with each other to form the product. For example, the general double displacement reaction between two compound AX and BY is as follows:
[tex]{\text{AX}}+{\text{BY}}\to{\text{AY}}+{\text{BX}}[/tex]
Examples of double displacement reactions are as follows:
(a) [tex]{\text{N}}{{\text{a}}_2}{\text{S}}+{\text{HCl}}\to{\text{NaCl}}+{{\text{H}}_2}{\text{S}}[/tex]
(b) [tex]2{\text{KOH}}+{\text{Cu}}{\left({{\text{N}}{{\text{O}}_{\text{3}}}}\right)_2}\to2{\text{KN}}{{\text{O}}_3}+{\text{Cu}}{\left({{\text{OH}}}\right)_2}[/tex]
5. Combustion reactions:
These are the reactions that take place when hydrocarbons are burnt in the presence of oxygen to form carbon dioxide and water. These are also referred to burning.
Example of combustion reactions are as follows:
(a) [tex]{\text{C}}{{\text{H}}_4}+{{\text{O}}_2}\to{\text{C}}{{\text{O}}_2}+{{\text{H}}_2}{\text{O}}[/tex]
(b) [tex]{{\text{C}}_{10}}{{\text{H}}_{14}}+12{{\text{O}}_2}\to10{\text{C}}{{\text{O}}_2}+4{{\text{H}}_2}{\text{O}}[/tex]
The given reaction occurs as follows:
[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{3}}}\left(s\right)+{\text{2HCl}}\left({aq}\right)\to{\text{2NaCl}}\left({aq}\right)+{\text{S}}{{\text{O}}_{\text{2}}}\left(g\right)+{{\text{H}}_{\text{2}}}{\text{O}}\left(l\right)[/tex]
This is an example of a double displacement reaction. Here [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_3}[/tex] reacts with HCl to form NaCl, [tex]{\text{S}}{{\text{O}}_2}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] . Of all the products formed, NaCl is present in the aqueous phase, [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] is in liquid state and [tex]{\text{S}}{{\text{O}}_2}[/tex] is in gaseous state.
So the gas formed in the above reaction is [tex]{\mathbf{S}}{{\mathbf{O}}_{\mathbf{2}}}[/tex] .
Learn more:
1. Identification of ionic bonding: https://brainly.com/question/1603987
2. Oxidation and reduction reaction: https://brainly.com/question/2973661
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Chemical reaction and equation
Keywords: SO2, Na2SO3, HCl, NaCl, H2O, double displacement reaction, combination reaction, combustion reaction, displacement reaction, decomposition reaction, aqueous, liquid, gaseous state.
