If v = 4.00 meters/second and makes an angle of 60° with the positive direction of the y–axis, what is the magnitude of vx?

Respuesta :

This velocity vector could then be pointing up and to the right or up and to the  left.  Since we only want the magnitude of the x-axis velocity, it doesn't matter.  In any case if there is a 60° angle from the y-axis means the sin of the angle gives the x-component.  (Typically the angle is given with respect to the x-axis in which the sin gives the y-component)
For this case
[tex]v_x=4sin(60)\frac{m}{s}=3.464 \frac{m}{s} [/tex]
3.46 m/s I just answered this question on a test I hope this helps :)