On a small planet, an astronaut uses a vertical
force of 175 newtons to lift an 87.5-kilogram
boulder at constant velocity to a height of
0.350 meter above the planet’s surface. What is
the magnitude of the gravitational field strength
on the surface of the planet?
(1) 0.500 N/kg (3) 9.81 N/kg
(2) 2.00 N/kg (4) 61.3 N/kg

Respuesta :

Boef
constant velocity means the netto force = 0, therefore F(gravity) = F(astronaut).
175N divided by 87,5kg = 2.00kg/N

Answer:

2.00 N/kg approximately.

Explanation:

A gravitational flied is defined as the quotient between the gravitational force and the mass:

[tex]g=\frac{F}{m}[/tex]

Replacing all given values, we have:

[tex]g=\frac{175N}{97.6kg}\\ g=1.96\frac{m}{s^{2} }[/tex]

Therefore, the gravitational filed is approximately 2.00 N/kg.