Respuesta :
Answer: Option B.
Since here the truck is moving on a circular track, it will experience centripetal force.
F(centripetal) = m × acc
or
[tex]r = \frac{m v^{2}}{F} [/tex]
where r is the radius of the track.
m is the mass of truck
v is the speed of the truck.
Given: v = 13 m/s
m = 1,600 kg
F = 3300 Newton
To find = radius of track=?
[tex]r = \frac{m v^{2} }{F} [/tex]
[tex]r = \frac{1600*13*13}{3300} [/tex]
r = 81.94 m
Therefore, radius of track is 81.94 m
Since here the truck is moving on a circular track, it will experience centripetal force.
F(centripetal) = m × acc
or
[tex]r = \frac{m v^{2}}{F} [/tex]
where r is the radius of the track.
m is the mass of truck
v is the speed of the truck.
Given: v = 13 m/s
m = 1,600 kg
F = 3300 Newton
To find = radius of track=?
[tex]r = \frac{m v^{2} }{F} [/tex]
[tex]r = \frac{1600*13*13}{3300} [/tex]
r = 81.94 m
Therefore, radius of track is 81.94 m
The Correct answer to this question for Penn Foster Students is: 81.94m