Air is heated in a glass bottle. The heat energy added to the air is 2.0 × 104 joules. What is the change in internal energy of the gas? Identify the thermodynamic process.

Respuesta :

The change in internal energy of the gas is [tex]\Delta U = 2.0 \cdot 10^4 J[/tex].

In fact, the 1st law of thermodynamics states that the change in internal energy of a system is equal to the amount of heat given to the system (Q) plus the work done on the system (W):
[tex]\Delta U = Q+W[/tex]
In this example, no work is done on the bottle so W=0, while the heat given to the system is [tex]Q=2.0 \cdot 10^4 J[/tex], so the change in internal energy of the gas is
[tex]\Delta U = Q = 2.0 \cdot 10^4 J[/tex]

Answer:

∆U = 2.0 × 104 J

Process: isovolumetric

Explanation:

Given: Q = 2 × 104 J,  

Find: internal energy, ∆U  

volume V remains constant, so W = 0  

∆U = Q – W  

∆U = Q  

∆U = 2.0 × 104 J

Process: isovolumetric