Suppose x has a normal distribution with mean μ = 45 and standard deviation σ = 9. describe the distribution of x values for sample size n = 4. (round σx to two decimal places.) μx = σx =

Respuesta :

The standard deviation of a particular sample is equal to the standard deviation divided by the square root of the sample size.  That is,[tex]\sigma_x=\frac{\sigma}{\sqrt n}[/tex]
The mean of a particular sample is equal to the mean of the set the sample was taken from.  That is,
[tex]\mu_x=\mu[/tex]
[tex]\text{In your case, }\sigma_x=\frac{9}{\sqrt4}=\frac92\text{ and }\mu_x=45.[/tex]