The assembly time for a product is uniformly distributed between 6 to 10 minutes. the probability of assembling the product in 7 minutes or more is:

Respuesta :

That probability is (10 -7)/(10 -6) = 3/4.

Using the uniform distribution, it is found that the probability of assembling the product in 7 minutes or more is 0.75 = 75%.

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An uniform distribution has two bounds, a and b.  

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

Uniformly distributed between 6 to 10 minutes, thus [tex]a = 6, b = 10[/tex].

The probability of assembling the product in 7 minutes or more is:

[tex]P(X > 7) = \frac{10 - 7}{10 - 6} = \frac{3}{4} = 0.75[/tex]

0.75 = 75% probability.

A similar problem is given at https://brainly.com/question/17088600