Respuesta :

[tex] \dfrac{n+1}{14} \times \dfrac{n+2}{n+1} [/tex]

Cancel the (n+1) on the numerator and the (n+1) on the denominator

[tex]= \dfrac{n+2}{14} [/tex]


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[tex] \dfrac{x-10}{4x} \div \dfrac{90-9x}{9x-90} [/tex]

Change the divide fraction to a multiplication fraction

[tex] \dfrac{x-10}{4x} \times \dfrac{9x-90}{90-9x} [/tex]

Take out common factors

[tex] \dfrac{-(10-x)}{4x} \times \dfrac{9(x-10)}{9(10-x)} [/tex]

The (10-x) from the numerator is cancel with (10-x) in the denominator
The 9 is also canceled

[tex] \dfrac{-1}{4x} \times \dfrac{(x-10)}1} [/tex]

Combine the fractions

[tex]- \dfrac{x-10}{4x} [/tex]

Simplify

[tex]\dfrac{10-x}{4x} [/tex]