A concession-stand manager buys bottles of water and soda to sell at a football game. The manager needs to buy a total of 4,500 drinks and have 25% more water than soda. Let w be the number of bottles of water and let s be the number of bottles of soda. Create a system of equations for w in terms of s that the manager could use to find out how many bottles of water and soda to buy.

Hey there
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The correct answer is
If s is soda, and w is water, then w=1.25s. So:
s+w=4500
s+1.25s=4500

2.25s=4500
s=2000
w=2500
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Hope this helps you

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omotayoadekoya1 omotayoadekoya1 · Answer 2 · 2020-02-10T17:15:40+01:00

Answer:

w = 1.25s and w + s = 4500

The manager needs to buy 2000 bottles of soda and 2500 bottles of water.

Step-by-step explanation:

If the manager needs to have 25% more water than soda and w is the number of bottles of water while s is the number of bottles of soda

Then;

w = s + 0.25s

w = 1.25s

As such, if the manager needs to buy a total of 4,500 drinks

Then it means that

w + s = 4500

1.25s + s = 4500

2.25s = 4500

s = 4500/2.25

s = 2000

w = 1.25 × 2000

w = 2500

The manager needs to buy 2000 bottles of soda and 2500 bottles of water.