A wrecking ball is basically a sphere. So, to solve this problem we are going to use the volume formula for a sphere: [tex]V= \frac{4}{3} \pi r^{3}[/tex]
where
[tex]r[/tex] is the radius of the sphere
We know for our problem that the diameter of the wrecking ball is 3.5 ft, so [tex]d=3.5[/tex]. To find its radius, we'll use the formula [tex]r= \frac{d}{2} [/tex]:
[tex]r= \frac{3.5}{2} [/tex]
[tex]r=1.75[/tex]
Now we can replace the radius in our formula to find the volume of our wrecking ball:
[tex]V= \frac{4}{3} \pi r^{3} [/tex]
[tex]V= \frac{4}{3} \pi (1.75)^{3}[/tex]
[tex]V=22.45[/tex]
We can conclude that the volume of our wrecking ball is 22.45 [tex]ft^{3}[/tex].
