In a lot (collection) of 100 light bulbs, there are 5 defective bulbs. an inspector inspects 10 bulbs selected at random. find the probability of finding at least one defec- tive bulb. hint: first compute the probability of finding no defectives in the sample.
Probability of finding no defective bulb =95/100*94/99....86/91 =95!/(85!) / (100!/90!) = 110983/190120 => Probability of finding at least one defective bulb =1-110983/190120 = 79137/190120 = 0.41625 (to 5 decimal places)
