We will be using division property of exponents.
The property is as follows:
[tex] \frac{x^{a}}{x^{b}} =x^{a-b} [/tex]
This means if we have same base in both numerator and denominator, the exponents will get subtracted.
In our question we have
[tex] \frac{4^{1}}{4^{3} } =4^{1-3} [/tex]
[tex] \frac{4^{1}}{4^{3} } =4^{-2} [/tex]
Now we will use another property of exponents here:
[tex] x^{-a} =\frac{1}{x^{a} } [/tex]
So if we take reciprocal of the above expression we will get,
[tex] 4^{-2} =\frac{1}{4^{2} } [/tex]
Rewriting the final answer:
[tex] \frac{6^{3} }{4^{2} } [/tex]
