Answer:
B) The maximum height is 11.3 ft and it reaches this height at 0.72
seconds.
Explanation:
Part (a) : getting the
time taken to reach maximum height:
The given equation is:
h = -16t² + V0*t + h0
We are given that:
Initial velocity (V0) =23 ft/sec
Initial height (h0) = 3 ft
The equation now becomes:
h = -16t² + 23t + 3
For maximum height:
dh / dt = zero
This means that:
-16(2) t + 23 = 0
-32t + 23 = 0
32t = 23
t = 0.71875 sec which is approximately 0.72 seconds
Part (b): getting the
maximum height:
The equation given to get the height is:
h = -16t² + V0*t + h0
We are given that:
Initial velocity (V0) =23 ft/sec
Initial height (h0) = 3 ft
We have calculated that:
time taken to reach maximum height = 0.72 sec
Substitute with the givens in the equation to get the maximum
height as follows:
h = -16t² + V0*t + h0
h = -16(0.72)² + 23(0.72) + 3
h = 11.2656 ft which is approximately 11.3 ft
Hope this helps :)
Answer:
The correct answer is in 1.56 seconds
Step-by-step explanation:
The original answer is incorrect
