Correct answer: C) 1.6 g
Molarity is the moles of solute present per liter solution.
The given molarity of the solution is 0.01 M.
Volume of the solution = 1 L
Calculating the moles from molarity and volume:
[tex] Moles of CuSO_{4} = 0.01 \frac{mol}{L} * 1 L = 0.01 mol CuSO_{4} [/tex]
Converting moles to mass of copper sulfate:
[tex] 0.01 mol CuSO_{4} * \frac{159.61 g CuSO_{4}}{1 mol CuSO_{4}} = 1.6 g CuSO_{4} [/tex]
