Respuesta :
Part A:
3x²y²-xy²-2y²
(3x²+2x)+(-3x-2)
x(3x+2)-(3x+2)
(3x+2)(x-1)
y²(x-1)(3x+2)
Part B:
x²+6x+9
(x²+3x)+(3x+9)
x(x+3)+3(x+3)
(x+3)(x+3)
(x+3)²
Part C:
x²-25
x²-5²
apply difference of squares rule: x²-y²=(x+y)(x-y)
x²-5²=(x+5)(x-5)
(x+5)(x-5)
I hope this helps!! let me know!!!
3x²y²-xy²-2y²
(3x²+2x)+(-3x-2)
x(3x+2)-(3x+2)
(3x+2)(x-1)
y²(x-1)(3x+2)
Part B:
x²+6x+9
(x²+3x)+(3x+9)
x(x+3)+3(x+3)
(x+3)(x+3)
(x+3)²
Part C:
x²-25
x²-5²
apply difference of squares rule: x²-y²=(x+y)(x-y)
x²-5²=(x+5)(x-5)
(x+5)(x-5)
I hope this helps!! let me know!!!