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There are fifteen teams in a high school baseball league. How many different orders of finish are possible for the first four ​positions?
There are
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nothing different orders of finish for the first four positions.

Respuesta :

There are 32,760 different orders for the first four positions.

This is a permutation where repetition is not allowed; the formula for that is:

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

For our problem, we have:
[tex]_{15}P_4=\frac{15!}{(15-4)!}=\frac{15!}{11!}=32760[/tex]
MrRoyal

There are 32760 different orders of finish for the first four positions.

How to determine the number of orders?

The given parameters are:

Teams = 15

Positions = 4

The order of the teams are:

  • The first position can be taken by any of the 15 teams
  • The second position can be taken by any of the remaining 14 teams
  • The third position can be taken by any of the remaining 13 teams
  • The fourth position can be taken by any of the remaining 12 teams

So, the number of orders is:

Order = 15 * 14 * 13 * 12

Evaluate

Order = 32760

Hence, there are 32760 different orders of finish for the first four positions.

Read more about permutation at:

https://brainly.com/question/11732255

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