Respuesta :
Well 123.75 divided by 0.25 is 495 so he had 495 quarters
x= # quarters
y= # dimes
QUANTITY EQUATION
x + y= 600
COST EQUATION
$0.25x + $0.10y= $123.75
STEP 1
Solve for one variable in the quantity equation
x + y= 600
subtract y from both sides
x= 600 - y
STEP 2
substitute x= 600-y in cost equation
$0.25x + $0.10y= $123.75
0.25(600-y) + 0.10y= 123.75
(0.25*600) + (0.25*-y) + 0.10y= 123.75
150 - 0.25y + 0.10y= 123.75
150 - 0.15y= 123.75
subtract 150 from both sides
-0.15y= -26.25
divide both sides by -0.15
y= 175 dimes
STEP 3
Substitute y= 175 in either equation to solve for number of quarters
x + y= 600
x + 175= 600
subtract 175 from both sides
x= 425 quarters
CHECK:
$0.25x + $0.10y= $123.75
0.25(425) + 0.10(175)= 123.75
106.25 + 17.50= 123.75
123.75= 123.75
ANSWER: There are 425 quarters
Hope this helps! :)
y= # dimes
QUANTITY EQUATION
x + y= 600
COST EQUATION
$0.25x + $0.10y= $123.75
STEP 1
Solve for one variable in the quantity equation
x + y= 600
subtract y from both sides
x= 600 - y
STEP 2
substitute x= 600-y in cost equation
$0.25x + $0.10y= $123.75
0.25(600-y) + 0.10y= 123.75
(0.25*600) + (0.25*-y) + 0.10y= 123.75
150 - 0.25y + 0.10y= 123.75
150 - 0.15y= 123.75
subtract 150 from both sides
-0.15y= -26.25
divide both sides by -0.15
y= 175 dimes
STEP 3
Substitute y= 175 in either equation to solve for number of quarters
x + y= 600
x + 175= 600
subtract 175 from both sides
x= 425 quarters
CHECK:
$0.25x + $0.10y= $123.75
0.25(425) + 0.10(175)= 123.75
106.25 + 17.50= 123.75
123.75= 123.75
ANSWER: There are 425 quarters
Hope this helps! :)