The minimum frequency is
[tex]f_1 = 550 kHz = 5.50 \cdot 10^5 Hz[/tex]
while the maximum frequency is
[tex]f_2 = 1600 kHz = 1.6 \cdot 10^6 Hz[/tex]
Using the relationship between frequency f of a wave, wavelength [tex]\lambda [/tex] and the speed of the wave v, we can find what wavelength these frequencies correspond to:
[tex]\lambda_1 = \frac{v}{f_1}= \frac{3 \cdot 10^8 m/s}{5.5 \cdot 10^5 Hz}=545 m [/tex]
[tex]\lambda_2 = \frac{v}{f_2}= \frac{3 \cdot 10^8 m/s}{1.6 \cdot 10^6 Hz}=188 m [/tex]
So, the wavelengths of the radio waves of the problem are within the range 188-545 m.
