Let's convert the final speed of the car into m/s:
[tex]v=95 km/h = 26.4 m/s[/tex]
We can find the acceleration of the car by using:
[tex]2aS= v_f^2-v_i^2[/tex]
where vi=0 is the initial speed of the car, vf=26.4 m/s the final speed, a the acceleration and S=125 m is the distance covered.
By substituting numbers and re-arranging the formula, we find:
[tex]a= \frac{v_f^2-v_i^2}{2S}= \frac{(26.4 m/s)^2}{2\cdot 125 m}=2.79 m/s^2 [/tex]
And then, we find the force by using Newton's second law:
[tex]F=ma=(950 kg)(2.79 m/s^2)=2651 N[/tex]
