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What is the wavelength of a 2.0 mhz ultrasound wave traveling through aluminum? assume that the speed of sound in aluminum is 5100 m/s. express your answer using two significant figures. λ = 2.6 mm submitprevious answers correct part b what frequency of electromagnetic wave would have the same wavelength as the ultrasound wave of part a?

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skyluke89
(a) The relationship between wavelength [tex]\lambda[/tex], frequency f and velocity v of a wave is
[tex]v=\lambda f[/tex]
For the sound wave of our problem, the frequency is [tex]f=2.0 MHz=2\cdot 10^6 Hz[/tex] while the velocity is [tex]v=5100 m/s[/tex], so its wavelength is 
[tex]\lambda = \frac{v}{f} = \frac{5100 m/s}{2 \cdot 10^6 Hz} =2.6 \cdot 10^{-3}m=2.6 mm[/tex]

(b) The only difference here is the velocity, because the speed of an electromagnetic wave is equal to the speed of light:
[tex]v=c=3 \cdot 10^8 m/s[/tex]
So, if we use the wavelength we found in the previous part, we get the frequency of the electromagnetic wave 
[tex]f= \frac{c}{\lambda}= \frac{3\cdot 10^8 m/s}{2.6 \cdot 10^{-3}m}=1.5 \cdot 10^{11}Hz [/tex]
okpalawalter8

The wavelength and the frequency  is mathematically given as

a)w= 2.55 mm

b)f=0.13 MHz

Wavelength and  frequency

Question Parameters:

the wavelength of a 2.0 mhz ultrasound wave traveling through aluminum

. λ = 2.6 mm submitprevious

the speed of sound in aluminum is 5100 m/s.

Generally the equation for the wavelength  is mathematically given as

w=v/f

Therefore

w= 5100 / 2*10^6

w= 2.55 mm

b)

f=v/w

Therefore

f= 333 / 0.00255

f=0.13 MHz

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