The μ rms speed = 475,433 m / s
Further explanation
Gas particles move randomly (both speed and direction, as vector)
Average velocities of gases can be expressed as root-mean-square velocity. (μ rms)
[tex]\rm \mu=\sqrt{\dfrac{3RT}{M_m} }[/tex]
R = gas constant, 8,314 J / mol K
T = temperature,
K
Mm = molar mass of the gas particles
, Kg
μ rms = root mean square velocity of Gas Particles.,m/s
From this equation shows that the velocity of the gas is inversely proportional to the molar mass of the gas particles
μ ≅ 1 / Mm
So that the greater the molar mass of the gas particles, the smaller the speed (the slowest)
Oxygen gas molecule, O₂ has a molar mass: 0.032 kg / mol
T = 17 °C = 17 + 273 = 290 K
then:
[tex]\rm \mu=\sqrt{\dfrac{3\times8.314\times 290}{0.032} }\\\\\mu_{rms}=475,433\:\frac{m}{s}[/tex]
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