So the quadrilateral is a rhombus. RSM Is hard and etc...
Anyways if the area =[tex]58^{2} [/tex] and we know that one diagonal is 14.5 inches and we know that the area of a rhombus is
[tex] \frac{D^{1} * D^{2}}{2} = [/tex]
then we can do inverse operation and do
[tex] \frac{54}{14.5} = 4 [/tex]
4 * 2 because of the inverse operation has to be done to get the right answer and then you get the length of diagonal 2 is 8 in
