Respuesta :

When Be(OH)₂ dissolves it dissociates into the following ions
Be(OH)₂ --> Be²⁺ + 2OH⁻
molar solubility is the number of moles that dissolve in 1 L of solution
If the molar solubility of Be(OH)₂ is 'x', molar solubility of Be²⁺ and OH⁻ ions are x and 2x respectively.
ksp is solubility constant for Be(OH)₂
ksp = [Be²⁺][OH⁻]²
6.92 * 10⁻²² = [x][2x]²
4x³ = 6.92 * 10⁻²²
x³ = 1.73 * 10⁻²²
x = 5.57 * 10⁻⁸ mol/L
molar solubility of Be(OH)₂ is 5.57 * 10⁻⁸ mol/L

The molar solubility of Be(OH)₂ is 5.57 × 10⁻⁸ mol/L

[tex]K_{sp}[/tex] of [tex]Be(OH)_2[/tex] = [tex]6.92 \times 10^{-22}[/tex]

It is required to calculate the molar solubility of the compound.

What is molar solubility?

The number of moles of a substance (the solute) that can be dissolved per liter of solution before the solution becomes saturated.

When Be(OH)₂ dissolves it dissociates into the following ions

Be(OH)₂ → Be²⁺ + 2OH⁻

consider the molar solubility of Be(OH)₂ is 'x', then the molar solubility of Be²⁺ and OH⁻ ions are x and 2x respectively.

[tex]K_{sp}[/tex] is solubility constant for Be(OH)₂

[tex]K_{sp}[/tex] = [Be²⁺][OH⁻]²

6.92 × 10⁻²² = [x][2x]²

4x³ = 6.92 × 10⁻²²

x³ = 1.73 × 10⁻²²

x = 5.57 × 10⁻⁸ mol/L

Hence, the molar solubility of Be(OH)₂ is 5.57 × 10⁻⁸ mol/L

To learn more about solubility, click here:

https://brainly.com/question/14092287?

Otras preguntas