A turist the distance between 2 cities which is 60 km made it on 2 days.The second day he made 5/7 of the road in the first day.Find the distance he walked on each day.

[tex] \frac{5}{7} x + x \\ = \frac{5 + 7}{7} \\ = \frac{12}{7} x \\ 60 = \frac{12}{7} x \\ x = 5 \times 7 = 35 [/tex]
The second day he made
[tex] \frac{5}{7} \times 35 \\ = \: 25 \: km[/tex]
the first day is 35 km

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Аноним Аноним · Answer 2 · 2018-03-25T17:21:50+02:00

Answer: Day 1 = 35 km ; Day 2 = 25 km

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Define x
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Let x be the distance the tourist walked on the first day

[tex]\text {First day = } x[/tex]

[tex]\text {Second day = } \dfrac{5}{7} x[/tex]

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Form equation and solve x
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Total distance = 60km

[tex]x + \dfrac{5}{7}x = 60 \ km[/tex]

[tex] \dfrac{12x}{7} = 60 \ km[/tex]

[tex]12x = 60 \times 7[/tex]

[tex]12x = 420[/tex]

[tex]x = 35[/tex]

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Find distance he walked on each day
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Day 1 = x = 35km

Day 2 = 5/7(35) = 25 km

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Answer: Day 1 = 35 km ; Day 2 = 25 km
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