Respuesta :
Add the x-coordinates and divide by 2.
Add the y-coordinates and divide by 2.
[tex] (\dfrac{10 + (-4)}{2}, \dfrac{-2 + 6}{2}) [/tex]
[tex] (\dfrac{6}{2}, \dfrac{4}{2}) [/tex]
[tex] (3, 2) [/tex]
Add the y-coordinates and divide by 2.
[tex] (\dfrac{10 + (-4)}{2}, \dfrac{-2 + 6}{2}) [/tex]
[tex] (\dfrac{6}{2}, \dfrac{4}{2}) [/tex]
[tex] (3, 2) [/tex]
The midpoint of a segment refers to the point in the middle of any segment. This can be find by using the formula, M=(x1+x2/2,y1+y2/2).
In this exercise is given that the segment JN, contains the points J and N, with coordinates (10,-2) and (-4,6) receptively. It is asked to find the midpoint of the segment, to do that you should substitute the given coordinates into the Midpoint Formula.
M=(x1+x2/2,y1+y2/2)
M=(10-4/2,-2+6/2)
M=(6/2,4/2)
M=(3,2)
The midpoint of the segment JN, is the coordinate (3,2).
In this exercise is given that the segment JN, contains the points J and N, with coordinates (10,-2) and (-4,6) receptively. It is asked to find the midpoint of the segment, to do that you should substitute the given coordinates into the Midpoint Formula.
M=(x1+x2/2,y1+y2/2)
M=(10-4/2,-2+6/2)
M=(6/2,4/2)
M=(3,2)
The midpoint of the segment JN, is the coordinate (3,2).