Which expressions show the volume and the surface area of this cubed-shaped packing box?

Answer:
[tex]V=(\frac{13}{8})^{3}\ ft^{3}[/tex], [tex]SA=6(\frac{13}{8})^{2}\ ft^{2}[/tex]
Step-by-step explanation:
we know that
The volume of a cube is equal to
[tex]V=b^{3}[/tex]
The surface area of a cube is equal to
[tex]SA=6b^{2}[/tex]
where b is the length side of the cube
In this problem we have
[tex]b=1\frac{5}{8}\ ft[/tex]
Convert to an improper fraction
[tex]b=1\frac{5}{8}=\frac{1*8+5}{8}=\frac{13}{8}\ ft[/tex]
Part 1) Find the volume
substitute the value of b in the formula
[tex]V=(\frac{13}{8})^{3}\ ft^{3}[/tex]
Part 2) Find the Surface area
substitute the value of b in the formula
[tex]SA=6(\frac{13}{8})^{2}\ ft^{2}[/tex]
Answer:
V=(13/8)3ft3; SA=6⋅(13/8)2ft2
Step-by-step explanation: