Felicity recorded the number of laps she swam each month for 7 months.Her data is shown.
112,134,150,98,120,68,116
Which is the mean absolute deviation to the nearest whole number of Felicity's lap data?
A.16
B.18
C.20
D.36

Question

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25-03-2018
Mathematics

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Felicity recorded the number of laps she swam each month for 7 months.Her data is shown.
112,134,150,98,120,68,116
Which is the mean absolute deviation to the nearest whole number of Felicity's lap data?
A.16
B.18
C.20
D.36

Respuesta :

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MsEHolt MsEHolt · Answer 1 · 2018-04-04T01:36:07+02:00

The mean absolute deviation is 18.

We first find the mean. Find the sum of all of the data points and divide by 7, the number of data points:

(112+134+150+98+120+68+116)/7 = 798/7 = 114

Now we subtract the mean from each data point, find the absolute value of each one, find their sum, and divide by the number of data points:

(|112-114|+|134-114|+|150-114|+|98-114|+|120-114|+|68-114|+|116-114|)/7
= (2+20+36+16+6+46+2)/7 = 128/7 = 18

Felicity recorded the number of laps she swam each month for 7 months.Her data is shown. 112,134,150,98,120,68,116 Which is the mean absolute deviation to the nearest whole number of Felicity's lap data? A.16 B.18 C.20 D.36

Respuesta :

Otras preguntas

Felicity recorded the number of laps she swam each month for 7 months.Her data is shown.
112,134,150,98,120,68,116
Which is the mean absolute deviation to the nearest whole number of Felicity's lap data?
A.16
B.18
C.20
D.36