Respuesta :
Let's call the lengths of our two types of sides [tex]x[/tex] and [tex]y[/tex].
The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus, [tex]x = y + 1.3[/tex].
Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
[tex](y + 1.3) + (y + 1.3) + y = 3y + 2.6 = 8[/tex]
Now, let's solve for y.
[tex]3y + 2.6 = 8[/tex]
[tex]3y = 5.4[/tex]
[tex]y = 1.8[/tex]
Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is [tex]y + 1.3 = 1.8 + 1.3 = \boxed{3.1}[/tex] inches and the length of our smaller side is simply [tex]\boxed{1.8}[/tex] inches.
To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus, [tex]x = y + 1.3[/tex].
Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
[tex](y + 1.3) + (y + 1.3) + y = 3y + 2.6 = 8[/tex]
Now, let's solve for y.
[tex]3y + 2.6 = 8[/tex]
[tex]3y = 5.4[/tex]
[tex]y = 1.8[/tex]
Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is [tex]y + 1.3 = 1.8 + 1.3 = \boxed{3.1}[/tex] inches and the length of our smaller side is simply [tex]\boxed{1.8}[/tex] inches.
To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
The length of the two equal sides of a triangle is 3.1 inches long. The length of third side, which is 1.3 inches shorter than other sides is 1.8 inches.
What is the perimeter of a triangle?
The measure of the boundary of the sides of a square is called its perimeter. The perimeter of a triangle is the sum of all the three sides of it.
[tex]P=a+b+c[/tex]
Here, (a,b,c) are the sides of the triangle.
Two of its sides are equal, and each of them is 1.3 inches bigger than the third side. Let the length of equal sides is x meters. Thus, the length of the shorter side is,
[tex](x-1.3)[/tex]
The perimeter of a triangle equals 8 inches. Thus,
[tex]x+x+(x-1.3)=8\\3x=8+1.3\\3x=9.3\\x=\dfrac{9.3}{3}\\x=3.1\rm\; in[/tex]
The length of the third side is,
[tex]x-1.3=3.1-1.3=1.8[/tex]
Thus, the length of the two equal sides of a triangle is 3.1 inches long. The length of third side, which is 1.3 inches shorter than other sides is 1.8 inches.
Learn more about the perimeter of the triangle here;
https://brainly.com/question/1763610
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