Answer:
358,800
Step-by-step explanation:
To find the number of possible passwords, we use the permutation formula:
[tex]_{n}P_{k}=\dfrac{n!}{(n-k)!}[/tex]
Our variables are:
n = 26
k = 4
[tex]_{26}P_{4}=\dfrac{26!}{(26-4)!}[/tex]
[tex]_{26}P_{4}=\dfrac{26!}{22!}[/tex]
[tex]_{26}P_{4}=358,800[/tex]
There are 358,800 possible password when there are 4 characters