Respuesta :

---------------------------------------------
Equation Given
---------------------------------------------
[tex]2x^2 + 8x = x^2 -16[/tex]

---------------------------------------------
Subtract x² + 16 from both sides
---------------------------------------------
[tex]2x^2 -x^2 + 8x + 16 = 0[/tex]

---------------------------------------------
Combine like terms
---------------------------------------------
[tex]x^2 + 8x + 16 = 0[/tex]

---------------------------------------------
Factorize
---------------------------------------------
[tex](x + 4)^2 = 0[/tex]

---------------------------------------------
Square root both sides
---------------------------------------------
[tex]x + 4 = 0[/tex]

---------------------------------------------
Take away 4 from both sides
---------------------------------------------
[tex]x = - 4[/tex]

---------------------------------------------
Answer: x =  - 4
---------------------------------------------
garydesir1
Hello there!

2x² + 8x = x² - 16

Let start by subtracting x² - 16 on both sides

2x² + 8x - x² - 16 = x² - 16 - x² - 16

x² + 8x - 16 = 0

Now we can factorize the left side

(x + 4)(x + 4) = 0

Set factors equal to 0

x + 4 = 0 or x + 4 = 0

x = 0 - 4 or x = 0 - 4

x = -4

Thus,

The only solution is -4

As always, it is my pleasure to help students like you!

Otras preguntas