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Monte performs an experiment using 2 identical graduated cylinders, each with a radius of 2 centimeters. The volume of the liquid in the first graduated cylinder is 188.4 cubic centimeters. The volume of the liquid in the second graduated cylinder is 314 cubic centimeters.

What is the difference in the height of the liquid in the two cylinders?

Use 3.14 for pi.               PLZZ I NEED ANSER FAST

Respuesta :

amendenhall
Recall the formula for the volume of a cylinder: [tex]V=\pi r^2h[/tex]

Let's plug in: [tex]188.4=3.14\cdot2^2h_1[/tex] so [tex]h_1=15[/tex].  [tex]314=3.14\cdot2^2h_2[/tex] so [tex]h_2=25[/tex]

The difference between [tex]h_1\text{ and }h_2[/tex] is 25-15=10 cm.

The difference in the height of the liquid in the two cylinders is; 10 cm

We are given;

Radius of cylinders; r = 2 cm

Volume of first cylinder; V1 = 188.4 cm³

Volume of second cylinder; V2 = 314 cm³

π = 3.14

Now, formula for volume of a cylinder is;

V = πr²h

Making h the subject;

h = V/πr²

For cylinder 1;

h1 = 188.4/(3.14 × 2²)

h1 = 15 cm

For cylinder 2;

h2 = 314/(3.14 × 2²)

h2 = 25 cm

Difference in the height of the two cylinders is;

Δh = h2 - h1

Δh = 25 - 15

Δh = 10 cm

Read more about volume of cylinder at; https://brainly.com/question/9554871

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