Respuesta :
3z + 1 = 4z + 19
Subtract 4z from each side
3z + 1 − 4z = 4z + 19 − 4z
−z + 1 = 19
Subtract 1 from each side
−z + 1 − 1 = 19 − 1
−z = 18
Divide each side by -1
-z ÷ -1 = 18 ÷ -1
z = -18
Subtract 4z from each side
3z + 1 − 4z = 4z + 19 − 4z
−z + 1 = 19
Subtract 1 from each side
−z + 1 − 1 = 19 − 1
−z = 18
Divide each side by -1
-z ÷ -1 = 18 ÷ -1
z = -18