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Suppose that 9 green balls and 13 purple balls are placed in an urn. two balls are then drawn in succession. what is the probability that both balls drawn have the same color if the first ball is replaced before the second is drawn?

Respuesta :

Total balls = 9 + 13 = 22

P(both green or both purple) = (9/22)(9/22) + (13/22)(13/22) = 125/242

Answer: 125/242
adioabiola

The probability that both balls drawn have the same colour if the first ball is replaced before the second is drawn is; 125/242

Total number of balls = 9 + 13 = 22

The probability of both balls having the same colour can be evaluated as;

  • P (both green or both purple) = (9/22)² + (13/22)²

  • P (GG or PP) = 250/484

P(GG or PP) = 125/242

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https://brainly.com/question/20140376

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