ijohnh14
ijohnh14
23-04-2018
Mathematics
contestada
can someone help me with this and explain please
Respuesta :
Аноним
Аноним
23-04-2018
[tex] \dfrac{4x^3y + 12x^2y^3- 20xy}{4xy} [/tex]
[tex]= \dfrac{4xy(x^2 + 3xy^2- 5)}{4xy} [/tex]
[tex]x^2 + 3xy^2- 5[/tex]
Answer: Option D
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