Answer: [tex]\frac{7}{10}[/tex]
Step-by-step explanation:
Here, The total dishes = 10
Dishes having meat = 3 ( chicken, meatloaf and hamburger )
Thus, the probability of having meat on the chosen dishes = Number of dishes having meat / Total dishes
= [tex]\frac{3}{10}[/tex]
Therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes
= [tex]1 - \frac{3}{10}[/tex]
= [tex]\frac{10-3}{10}[/tex]
= [tex]\frac{7}{10}[/tex]
⇒ Option b is correct.
