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In △ABC, AC=12 in., BC=1.5 in., and m∠C=63°. What is the area of △ABC? Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth. in²

Respuesta :

calculista
we know that

applying the law of sines

Area of triangle=(1/2)*a*b*sin C

n this problem

a=BC----> 1.5 in

b=AC----> 12 in

C=63°

Area of triangle=(1/2)*1.5*12*sin 63°------> 8.0191 in²------> 8.02 in²


the answer is

8.02 in²

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