In the reaction of aluminum metal with hydrochloric acid, if 5.50 g of aluminum is reacted with excess acid at 25 c and 0.975 atm, how many liters of hydrogen gas would be produced? 2al(s) + 6hcl(aq) → 2alcl3(aq) + 3h2(g)

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Liters are the measurement unit of the volume used to know the amount of space occupied by the substance. 7.5 2 L of hydrogen gas would be produced.

What is the ideal gas equation?

An ideal gas equation states the direct relationship between the volume and temperature and the indirect with the pressure.

The balanced chemical reaction is shown as,

[tex]\rm 2Al(s) + 6HCl(aq) \rightarrow 2AlCl_{3}(aq) + 3H_{2}(g)[/tex]

Given,

The temperature of the gas = 298 K

The pressure of the gas = 0.975 atm

Moles of aluminum are calculated as:

[tex]\begin{aligned} \rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{5.50}{27}\\\\&= 0.2037 \;\rm atm\end{aligned}[/tex]

Moles of hydrogen are calculated as:

[tex]\begin{aligned} &= \dfrac{3}{2} \times \text{moles of alumium} \\\\&= \dfrac{3}{2} \times 0.2037\\\\&= 0.3 \;\rm mol\end{aligned}[/tex]

The volume of hydrogen gas is calculated as:

[tex]\begin{aligned} \rm V &= \rm \dfrac{nRT}{P}\\\\&= \dfrac{0.3 \times 0.082 \times 298}{0.975}\\\\&= 7.52 \;\rm L\end{aligned}[/tex]

Therefore, 7.52 L of hydrogen gas is produced.

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