Equation is as follow,
Cl₂ + 2 KBr → 2 KCl + Br₂
According to equation,
238 g (2 moles) KBr produced = 2 Moles of KCl
So,
331.1 g of KBr will produce = X moles of KCl
Solving for X,
X = (331.1 g × 2 mol) ÷ 238 g
X = 2.78 Moles of KCl
Result:
331.1 g of KBr produces 2.78 Moles of KCl.
