Respuesta :
[tex]2 H_{2} + O_{2} ---\ \textgreater \ 2H_{2}O
[/tex]
[tex]K= \frac{ [H_{2}O]^{2} }{ [H_{2}]^{2} [O_{2}]} [/tex]
[tex]K= \frac{ [H_{2}O]^{2} }{ [H_{2}]^{2} [O_{2}]} [/tex]
Answer:
The expression for an equilibrium constant for the given reaction:
[tex]K_c=\frac{[H_2O]^2}{[H_2]^2[O_2}}[/tex]
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_{eq}[/tex]
K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
For the given chemical reaction:
[tex]2H_2+O_2\rightleftharpoons 2H_2O[/tex]
The expression for an equilibrium constant will be given by:
[tex]K_c=\frac{[H_2O]^2}{[H_2]^2[O_2}}[/tex]
