Data Given:
P₁ = 153.3 kPa
V₁ = 25.5 L
T₁ = 298 K
P₂ = 101.325 kPa
V₂ = ?
T₂ = 273 K
Solution:
Suppose the gas is acting Ideally, then According to Ideal Gas Equation,
P₁ V₁ / T₁ = P₂ V₂ / T₂
Solving for V₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting Values,
V₂ = (153.3 kPa × 25.5 L × 273 K) ÷ (298 K × 101.325 kPa)
V₂ = 35.34 L
Result:
35.34 L volume is occupied at STP.